A drawing room is 7.5 text{ m} long,6.5 text{ | vedclass

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(B) The dimensions of the room are: length $(l) = 7.5 	ext{ m}$,breadth $(b) = 6.5 	ext{ m}$,and height $(h) = 6 	ext{ m}$.Area of the four walls $

Vedclass · Accepted Answer

$640$

Vedclass · Answer

(B) The dimensions of the room are: length $(l) = 7.5 	ext{ m}$,breadth $(b) = 6.5 	ext{ m}$,and height $(h) = 6 	ext{ m}$.Area of the four walls $= 2(l + b) 	imes h = 2(7.5 + 6.5) 	imes 6 = 2(14) 	imes 6 = 168 	ext{ m}^2$.Area to be covered by paper $=$ Total area of walls $-$ Area of doors $= 168 	ext{ m}^2 - 8 	ext{ m}^2 = 160 	ext{ m}^2$.Width of the paper $= 2.5 	ext{ dm} = 0.25 	ext{ m}$.Length of the paper $= \frac{	ext{Area to be covered}}{	ext{Width of paper}} = \frac{160}{0.25} = 640 	ext{ m}$.

$A$ drawing room is $7.5 \text{ m}$ long,$6.5 \text{ m}$ broad,and $6 \text{ m}$ high. Find the length of paper $2.5 \text{ dm}$ wide required to cover its walls,allowing $8 \text{ m}^2$ for doors.

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