A factory manufactures 120000 pencils daily. | vedclass

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(C) The curved surface area of a cylinder is given by $CSA = 2 \pi r h$,where $2 \pi r$ is the circumference of the base and $h$ is the length (height

Vedclass · Accepted Answer

$2250$

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(C) The curved surface area of a cylinder is given by $CSA = 2 \pi r h$,where $2 \pi r$ is the circumference of the base and $h$ is the length (height).Given,circumference of the base $= 1.5 \,cm$ and length $h = 25 \,cm$.Curved surface area of one pencil $= 1.5 \,cm 	imes 25 \,cm = 37.5 \,cm^2$.Since $1 \,dm = 10 \,cm$,then $1 \,dm^2 = 100 \,cm^2$. Therefore,$1 \,cm^2 = 0.01 \,dm^2$.Curved surface area of one pencil in $dm^2 = 37.5 	imes 0.01 = 0.375 \,dm^2$.Total curved surface area for $120000$ pencils $= 120000 	imes 0.375 \,dm^2 = 45000 \,dm^2$.Cost of colouring $= 45000 \,dm^2 	imes \operatorname{Rs.} 0.05/dm^2 = \operatorname{Rs.} 2250$.

$A$ factory manufactures $120000$ pencils daily. The pencils are cylindrical in shape,each of length $25 \,cm$ and circumference of base $1.5 \,cm$. Determine the cost of colouring the curved surfaces of the pencils manufactured in one day at $\operatorname{Rs.} 0.05$ per $dm^2$ (in $Rs.$).

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