(A) For a first order reaction,the half-life $(t_{1/2})$ is given by the formula:$t_{1/2} = \frac{0.693}{k}$Given $k = 5.5 \times 10^{-14} \ s^{-1}$.S

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) For a first order reaction,the half-life $(t_{1/2})$ is given by the formula:$t_{1/2} = \frac{0.693}{k}$Given $k = 5.5 \times 10^{-14} \ s^{-1}$.Substituting the value of $k$:$t_{1/2} = \frac{0.693}{5.5 \times 10^{-14} \ s^{-1}}$$t_{1/2} = 0.126 \times 10^{14} \ s = 1.26 \times 10^{13} \ s$.

Class 12 Chemistry Chemical Kinetics First Order reaction

Medium

$A$ first order reaction is found to have a rate constant,$k = 5.5 \times 10^{-14} \ s^{-1}$. Find the half-life of the reaction.

A
$1.26 \times 10^{13} \ s$
B
$2.52 \times 10^{13} \ s$
C
$0.63 \times 10^{13} \ s$
D
$1.26 \times 10^{14} \ s$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

First Order reaction

For a first order reaction $A \rightarrow B$, the data is provided in the table below. Find $x$ in minutes. (Nearest integer)
$t/\text{min}$ $[A]/M$
$0$ $0.6500$
$x$ $0.0650$
$20$ $0.00065$

$t/\text{min}$	$[A]/M$
$0$	$0.6500$
$x$	$0.0650$
$20$	$0.00065$

DifficultJEE MAIN 2026

View Solution

The half-life of a first-order reaction is $2000$ years. If the concentration after $8000$ years is $0.02 \, M$,then the initial concentration was $........... \, M$.

DifficultNEET 2022

View Solution

$75\%$ of a first order reaction is completed in $30 \ min$. What is the time required for $93.75\%$ of the reaction (in minutes)?

Medium

View Solution

For the first order reaction with rate constant $k$,which expression gives the half-life period? (Initial concentration $= a$)

Easy

View Solution

If $60\%$ of a first order reaction was completed in $60 \ min$,$50\%$ of the same reaction would be completed in approximately $.......... \ min.$
$(\log \, 4 = 0.60, \, \log \, 5 = 0.69)$

MediumAIPMT 2007

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ first order reaction is found to have a rate constant,$k = 5.5 \times 10^{-14} \ s^{-1}$. Find the half-life of the reaction.

Similar Questions

For a first order reaction $A \rightarrow B$, the data is provided in the table below. Find $x$ in minutes. (Nearest integer)$t/\text{min}$$[A]/M$$0$$0.6500$$x$$0.0650$$20$$0.00065$

The half-life of a first-order reaction is $2000$ years. If the concentration after $8000$ years is $0.02 \, M$,then the initial concentration was $........... \, M$.

$75\%$ of a first order reaction is completed in $30 \ min$. What is the time required for $93.75\%$ of the reaction (in minutes)?

For the first order reaction with rate constant $k$,which expression gives the half-life period? (Initial concentration $= a$)

If $60\%$ of a first order reaction was completed in $60 \ min$,$50\%$ of the same reaction would be completed in approximately $.......... \ min.$$(\log \, 4 = 0.60, \, \log \, 5 = 0.69)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

For a first order reaction $A \rightarrow B$, the data is provided in the table below. Find $x$ in minutes. (Nearest integer)
$t/\text{min}$ $[A]/M$
$0$ $0.6500$
$x$ $0.0650$
$20$ $0.00065$

If $60\%$ of a first order reaction was completed in $60 \ min$,$50\%$ of the same reaction would be completed in approximately $.......... \ min.$
$(\log \, 4 = 0.60, \, \log \, 5 = 0.69)$