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(D) Let the initial velocity be $\vec{V}_i = V(-\hat{j})$ (southward).Let the final velocity be $\vec{V}_f = V(\hat{i})$ (eastward).The change in velo

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along north-east

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(D) Let the initial velocity be $\vec{V}_i = V(-\hat{j})$ (southward).Let the final velocity be $\vec{V}_f = V(\hat{i})$ (eastward).The change in velocity is given by $\Delta\vec{V} = \vec{V}_f - \vec{V}_i$.Substituting the values,we get $\Delta\vec{V} = V\hat{i} - (-V\hat{j}) = V\hat{i} + V\hat{j}$.Since force $\vec{F} = m\vec{a} = m\frac{\Delta\vec{V}}{\Delta t}$,the direction of the force is the same as the direction of the change in velocity $\Delta\vec{V}$.The vector $V\hat{i} + V\hat{j}$ points in the north-east direction.Therefore,the force acts along north-east.

$A$ football player is moving southward and suddenly turns eastward with the same speed to avoid an opponent. The force that acts on the player while turning is:

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