$A$ force of $98 \, N$ is required to just start moving a body of mass $100 \, kg$ over ice. The coefficient of static friction is

  • A
    $0.6$
  • B
    $0.4$
  • C
    $0.2$
  • D
    $0.1$

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$A$ force of $19.6\, N$ when applied parallel to the surface just moves a body of mass $10\, kg$ kept on a horizontal surface. If a $5\, kg$ mass is kept on the first mass,the force applied parallel to the surface to just move the combined body is........ $N.$

How does static friction oppose motion? On which factors does the value of the coefficient of friction depend?

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To avoid slipping while walking on ice,one should take smaller steps because of the

If the mass of block $A = 10\,kg$,the coefficient of static friction $\mu_s = 0.2$,and the coefficient of kinetic friction $\mu_k = 0.2$,find the mass of block $B$ required to start the motion.

The maximum value of static friction is called:

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