$A$ force of $50 \text{ dynes}$ acts on a body of mass $5 \text{ g}$ which is at rest for an interval of $3 \text{ seconds}$. The impulse is:

How can we draw a two-object $FBD$ (Free Body Diagram) according to Newton's third law?

The figure shows the position-time $(x-t)$ graph of one-dimensional motion of a body of mass $0.4 \; kg$. The magnitude of each impulse is:

$A$ particle of mass $1\, kg$ is acted upon by a force $F$ which varies as shown in the figure. If the initial velocity of the particle is $10\, ms^{-1}$, the maximum velocity attained by the particle during the period is ........ $ms^{-1}$.

$A$ body of mass $5 \,kg$ is moving with a velocity of $\vec{v}=(2 \hat{i}+6 \hat{j}) \,m/s$ at $t=0 \,s$. After time $t=2 \,s$,the velocity of the body is $(10 \hat{i}+6 \hat{j}) \,m/s$. The change in momentum of the body is ......... $kg \cdot m/s$.

Two particles of masses $m_1$ and $m_2$ in projectile motion have velocities $\vec{v}_1$ and $\vec{v}_2$ respectively at time $t = 0$. They collide at time $t_0$. Their velocities become $\vec{v}_1'$ and $\vec{v}_2'$ at time $2t_0$ while still moving in air. The value of $|(m_1\vec{v}_1' + m_2\vec{v}_2') - (m_1\vec{v}_1 + m_2\vec{v}_2)|$ is