A galvanometer G deflects full scale when a p | vedclass

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(A) To construct an ammeter from a galvanometer,we connect a shunt resistance $R_S$ in parallel with the galvanometer.The full-scale deflection curren

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$0.25$

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(A) To construct an ammeter from a galvanometer,we connect a shunt resistance $R_S$ in parallel with the galvanometer.The full-scale deflection current of the galvanometer $I_g$ is given by $I_g = \frac{V_g}{r_g} = \frac{0.50 \ V}{25 \ \Omega} = 0.02 \ A$.The total current $I$ to be measured is $2.0 \ A$. The current through the shunt resistance $I_S$ is $I_S = I - I_g = 2.0 \ A - 0.02 \ A = 1.98 \ A$.Since the galvanometer and shunt are in parallel,the potential difference across them is the same:$V_g = I_S 	imes R_S$$0.50 \ V = 1.98 \ A 	imes R_S$$R_S = \frac{0.50}{1.98} \ \Omega \approx 0.2525 \ \Omega$.Thus,the resistance $R_S$ is closest to $0.25 \ \Omega$.

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