(D) Let $G$ be the resistance of the galvanometer and $I_g = 0.006 \ A$ be the current for full scale deflection.For a voltmeter of range $V = 30 \ V$

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) Let $G$ be the resistance of the galvanometer and $I_g = 0.006 \ A$ be the current for full scale deflection.For a voltmeter of range $V = 30 \ V$ with a series resistance $R = 4990 \ \Omega$:$V = I_g(G + R)$$30 = 0.006(G + 4990)$$G + 4990 = \frac{30}{0.006} = 5000$$G = 5000 - 4990 = 10 \ \Omega$For an ammeter of range $I = 1.5 \ A$ with a shunt resistance $S = \frac{2n}{249} \ \Omega$:$I_g G = (I - I_g) S$$0.006 \times 10 = (1.5 - 0.006) \times S$$0.06 = 1.494 \times S$$S = \frac{0.06}{1.494} = \frac{60}{1494} = \frac{10}{249} \ \Omega$Equating the shunt resistance:$\frac{2n}{249} = \frac{10}{249}$$2n = 10 \Rightarrow n = 5$

Class 12 Physics Moving Charges and Magnetism The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Difficult

$A$ galvanometer gives full scale deflection with $0.006 \ A$ current. By connecting it to a $4990 \ \Omega$ resistance,it can be converted into a voltmeter of range $0-30 \ V$. If connected to a $\frac{2n}{249} \ \Omega$ resistance,it becomes an ammeter of range $0-1.5 \ A$. The value of $n$ is:

IIT 2014 All IIT

A
$2$
B
$3$
C
$4$
D
$5$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Moving Charges and Magnetism

Subtopic

The Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion

Previous Year

IIT 2014 Paper All IIT years →

$A$ moving coil galvanometer is converted into an ammeter of range $0$ to $5 \, mA$. The galvanometer resistance is $90 \, \Omega$ and the shunt resistance has a value of $10 \, \Omega$. If there are $50$ divisions in the galvanometer-turned-ammeter on either side of zero, its current sensitivity is

MediumKCET 2023

View Solution

$A$ millivoltmeter of $25 \, mV$ range is to be converted into an ammeter of $25 \, A$ range. The value (in $\Omega$) of the necessary shunt will be:

MediumAIPMT 2012

View Solution

$A$ galvanometer of resistance $G$ is shunted by a resistance of $5 \Omega$. To keep the main current in the circuit unchanged,the resistance to be put in series with the same galvanometer is

MediumMHT CET 2022

View Solution

$A$ moving coil galvanometer has $150$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \, V$,the resistance in $\Omega$ needed to be connected in series with the coil will be

MediumAIEEE 2005

View Solution

The sensitivity of a galvanometer is $60 \text{ division/A}$. When a shunt is used,its sensitivity becomes $10 \text{ division/A}$. If the galvanometer is of resistance $20 \ \Omega$,the value of shunt used is (in $\Omega$)

DifficultTS EAMCET 2011

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

$A$ galvanometer gives full scale deflection with $0.006 \ A$ current. By connecting it to a $4990 \ \Omega$ resistance,it can be converted into a voltmeter of range $0-30 \ V$. If connected to a $\frac{2n}{249} \ \Omega$ resistance,it becomes an ammeter of range $0-1.5 \ A$. The value of $n$ is:

Similar Questions

$A$ millivoltmeter of $25 \, mV$ range is to be converted into an ammeter of $25 \, A$ range. The value (in $\Omega$) of the necessary shunt will be:

$A$ galvanometer of resistance $G$ is shunted by a resistance of $5 \Omega$. To keep the main current in the circuit unchanged,the resistance to be put in series with the same galvanometer is

$A$ moving coil galvanometer has $150$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1 \, V$,the resistance in $\Omega$ needed to be connected in series with the coil will be

The sensitivity of a galvanometer is $60 \text{ division/A}$. When a shunt is used,its sensitivity becomes $10 \text{ division/A}$. If the galvanometer is of resistance $20 \ \Omega$,the value of shunt used is (in $\Omega$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module