$A$ galvanometer has $36\,\Omega$ resistance. If a $4\,\Omega$ shunt is added to this,the fraction of current that passes through the shunt is

  • A
    $\frac{1}{4}$
  • B
    $\frac{1}{9}$
  • C
    $\frac{1}{10}$
  • D
    $\frac{9}{10}$

Explore More

Similar Questions

An ammeter of $5\,\Omega$ resistance can read $5\,mA$. If it is to be used to read $100\,V$,how much resistance is to be connected in series? (in $\Omega$)

When a galvanometer is shunted with a $4\,\Omega$ resistance,the deflection is reduced to one-fifth. If the galvanometer is further shunted with a $2\,\Omega$ wire,the further reduction in the deflection will be (the main current remains same).

To convert a galvanometer into an ammeter,a shunt of $0.01\,\Omega$ is used. The resistance of the galvanometer coil is $50\,\Omega$ and its maximum deflection current is $20\,mA$. The range of the ammeter is:

Explain the difficulties encountered when using a galvanometer directly as an ammeter.

When a galvanometer is shunted by a resistance $s$,its current capacity increases $n$ times. If the same galvanometer is shunted by another resistance $s_1$,its capacity will increase to $n_1$ times the original current. The value of $n_1$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo