$A$ galvanometer has $30$ divisions and a sensitivity of $16\,\mu A/\text{div}$. It can be converted into a voltmeter to read $3\,V$ by connecting:

With a resistance $X$ connected in series with a galvanometer of resistance $100 \Omega$,it acts as a voltmeter of range $0-15 \ V$. To double the range,a resistance of $1500 \Omega$ is to be connected in series with $X$. The value of $X$ in ohm is:

$A$ galvanometer of resistance $50\, \Omega$ is connected to a battery of $3\, V$ along with a resistance of $2950\, \Omega$ in series. $A$ full-scale deflection of $30$ divisions is obtained in the galvanometer. In order to reduce this deflection to $20$ divisions,the resistance in series should be.......$\Omega$

$A$ galvanometer has resistance $G$ and range $V_g$. How much resistance is required to read voltage up to $V$ volt?

$A$ moving coil galvanometer has a rectangular wire coil of enclosed area $0.001 \ m^2$ and $500$ turns. The coil operates in a radial magnetic field of $0.2 \ T$ and carries a current of $6 \pi \times 10^{-8} \ A$. If the torsional spring constant is $6 \times 10^{-7} \ N-m/rad$, then the angular deflection of the coil in radians is

In the circuit shown below,the ammeter and the voltmeter readings are $3 \text{ A}$ and $6 \text{ V}$ respectively. Then the value of the resistance $R$ is