Class 12PhysicsMoving Charges and MagnetismThe Moving Coil Galvanometer (Sensitivity) and Ammeter and Voltmeter Conversion
Medium$A$ galvanometer having a coil resistance of $30\,\Omega$ shows full-scale deflection when a current of $2\,A$ passes through it. It can be converted into an ammeter to read currents up to $10\,A$ by:
- Aby putting in series a resistance of $240\,\Omega$
- Bby putting in parallel a resistance of $240\,\Omega$
- Cby putting in series a resistance of $7.5\,\Omega$
- Dby putting in parallel a resistance of $7.5\,\Omega$
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Similar Questions
$A$ $50\,\Omega$ resistance is connected to a battery of $5\,V$. $A$ galvanometer of resistance $100\,\Omega$ is to be used as an ammeter to measure current through the resistance. For this,a resistance $r_s$ is connected to the galvanometer. Which of the following connections should be employed if the measured current is within $1\%$ of the current without the ammeter in the circuit?
DifficultJEE MAIN 2016
View SolutionMatch the terms given in List-$I$ with suitable options provided in List-$II$ regarding the experiment to calculate the resistance and figure of merit of a galvanometer using the half-deflection method:
List-$I$ List-$II$ $A$. Figure of merit $(k)$ $P$. in series $B$. Current sensitivity $(SI)$ $Q$. to get power loss minimized $C$. Deflection is made half by using low resistance $R$. in shunt/parallel $D$. High resistance box $S$. current per unit deflection $T$. deflection per unit current
| List-$I$ | List-$II$ |
|---|---|
| $A$. Figure of merit $(k)$ | $P$. in series |
| $B$. Current sensitivity $(SI)$ | $Q$. to get power loss minimized |
| $C$. Deflection is made half by using low resistance | $R$. in shunt/parallel |
| $D$. High resistance box | $S$. current per unit deflection |
| $T$. deflection per unit current |
Medium
View Solution$A$ galvanometer gives a full-scale reading of $50 \ mA$,when a potential difference across its terminals is $0.15 \ V$. It can be used as an ammeter of range $0 - 100 \ A$ by connecting a shunt resistance of: (in $\Omega$)
Medium
View Solution$A$ current of $200 \ \mu A$ deflects the coil of a moving coil galvanometer through $60^{\circ}$. The current required to cause a deflection of $\frac{\pi}{10}$ radians is: (in $\mu A$)
DifficultJEE MAIN 2024
View SolutionIf only $\frac{1}{51}$ of the main current is to be passed through a galvanometer,then the shunt required is $R_1$. If only $\frac{1}{11}$ of the main voltage is to be developed across the galvanometer,then the resistance required is $R_2$. Find the ratio $\frac{R_2}{R_1}$.
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