A galvanometer of resistance 50,Omega is conn | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The initial total resistance in the circuit is $R_{total,1} = R_G + R_1 = 50\,\Omega + 2950\,\Omega = 3000\,\Omega$.Given the battery voltage $\va

Vedclass · Accepted Answer

$4450$

Vedclass · Answer

(B) The initial total resistance in the circuit is $R_{total,1} = R_G + R_1 = 50\,\Omega + 2950\,\Omega = 3000\,\Omega$.Given the battery voltage $\varepsilon = 3\,V$,the initial current $I_1$ is $I_1 = \frac{\varepsilon}{R_{total,1}} = \frac{3\,V}{3000\,\Omega} = 1 	imes 10^{-3}\,A = 1\,mA$.Since $30$ divisions correspond to $1\,mA$,the current per division is $\frac{1\,mA}{30}$.To get a deflection of $20$ divisions,the new current $I_2$ must be $I_2 = 20 	imes \frac{1\,mA}{30} = \frac{2}{3}\,mA$.Let the new total resistance be $R_{total,2}$. Using Ohm's law,$I_2 = \frac{\varepsilon}{R_{total,2}}$,so $R_{total,2} = \frac{\varepsilon}{I_2} = \frac{3\,V}{(2/3) 	imes 10^{-3}\,A} = 4500\,\Omega$.The new total resistance is $R_{total,2} = R_G + R_{new}$,where $R_{new}$ is the new series resistance.$4500\,\Omega = 50\,\Omega + R_{new} \Rightarrow R_{new} = 4450\,\Omega$.

Similar Questions

Le Chatelier's principle is not applicable to

What is the family of the tapioca plant?

The position vectors of two particles of masses $1 \, kg$ and $3 \, kg$ are $\hat{i} + 2\hat{j} + \hat{k}$ and $-3\hat{i} - 2\hat{j} + \hat{k}$ respectively. The position vector of the center of mass of the system of these particles is:

$A$ uniform beam of weight $W$ is attached to a vertical wall by a hinge $H$. The beam is held horizontal by a rope as shown below. Which one of the following best shows the direction of the reaction force $R$ at the hinge?

If $\int \frac{x-\sin x}{1+\cos x} dx = x \tan \left(\frac{x}{2}\right) + p \log \left|\sec \left(\frac{x}{2}\right)\right| + C$, then $p$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module