A galvanometer with a resistance of 12 ,Omega | vedclass

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(B) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.The formula for the series resi

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$5988$

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(B) To convert a galvanometer into a voltmeter,a high resistance $R$ must be connected in series with the galvanometer.The formula for the series resistance is given by $R = \frac{V}{I_g} - G$,where $V$ is the maximum voltage to be measured,$I_g$ is the full-scale deflection current,and $G$ is the galvanometer resistance.Given: $V = 18 \, V$,$I_g = 3 \, mA = 3 	imes 10^{-3} \, A$,and $G = 12 \, \Omega$.Substituting the values: $R = \frac{18}{3 	imes 10^{-3}} - 12$.$R = 6000 - 12 = 5988 \, \Omega$.Thus,a resistance of $5988 \, \Omega$ must be connected in series.

$A$ galvanometer with a resistance of $12 \,\Omega$ gives full-scale deflection when a current of $3 \, mA$ is passed. It is required to convert it into a voltmeter which can read up to $18 \, V$. The resistance to be connected is ............... $\Omega$.

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