A gas (gamma = 1.3) is enclosed in an insulat | vedclass

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(B) Since the process is sudden and the vessel is insulated,it is an adiabatic process. For an adiabatic process,the relation between pressure and vol

Vedclass · Accepted Answer

$2^{1.3} 	imes 10^5 \ N/m^2$

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(B) Since the process is sudden and the vessel is insulated,it is an adiabatic process. For an adiabatic process,the relation between pressure and volume is $PV^\gamma = 	ext{constant}$.Thus,$P_1 V_1^\gamma = P_2 V_2^\gamma$.Given: $P_1 = 10^5 \ N/m^2$,$\gamma = 1.3$,and $V_2 = \frac{V_1}{2}$.Substituting these values into the equation:$P_2 = P_1 \left( \frac{V_1}{V_2} ight)^\gamma$$P_2 = 10^5 	imes \left( \frac{V_1}{V_1/2} ight)^{1.3}$$P_2 = 10^5 	imes (2)^{1.3} \ N/m^2$.Therefore,the final pressure is $2^{1.3} 	imes 10^5 \ N/m^2$.

$A$ gas $(\gamma = 1.3)$ is enclosed in an insulated vessel fitted with an insulating piston at a pressure of $10^5 \ N/m^2$. On suddenly pressing the piston,the volume is reduced to half the initial volume. The final pressure of the gas is:

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