(C) When ethyl iodide $(CH_3-CH_2-I)$ reacts with alcoholic $KOH$,it undergoes dehydrohalogenation to form ethene $(C_2H_4)$.Ethene is an unsaturated

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(C) When ethyl iodide $(CH_3-CH_2-I)$ reacts with alcoholic $KOH$,it undergoes dehydrohalogenation to form ethene $(C_2H_4)$.Ethene is an unsaturated hydrocarbon that decolorizes alkaline $KMnO_4$ solution (Baeyer's reagent).The reaction is: $CH_3-CH_2-I + KOH (\text{alc.}) \rightarrow CH_2=CH_2 + KI + H_2O$.