$A$ gas is compressed isothermally to half its initial volume. The same gas is compressed separately through an adiabatic process until its volume is again reduced to half. Then

  • A
    Compressing the gas through adiabatic process will require more work to be done.
  • B
    Compressing the gas isothermally or adiabatically will require the same amount of work.
  • C
    Which of the case (whether compression through isothermal or through adiabatic process) requires more work will depend upon the atomicity of the gas.
  • D
    Compressing the gas isothermally will require more work to be done.

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$2$ moles of an ideal monoatomic gas is carried from a state $(p_{0}, V_{0})$ to state $(2 p_{0}, 2 V_{0})$ along a straight line path in a $p-V$ diagram. The amount of heat absorbed by the gas in the process is given by

Match the following:
List-$I$List-$II$
$i)$ Isothermal process$a)$ $0$
$ii)$ Isobaric process$b)$ $\frac{1}{\gamma-1}[P_2 V_2 - P_1 V_1]$
$iii)$ Isochoric process$c)$ $\mu RT \ln(\frac{V_2}{V_1})$
$iv)$ Adiabatic process$d)$ $P(V_2 - V_1)$

The correct answer is:

In thermodynamic processes, which of the following statements is not true?

$A$ monoatomic gas of $n$-moles is heated from temperature $T_1$ to $T_2$ under two different conditions: $(i)$ at constant volume and (ii) at constant pressure. The change in internal energy of the gas is

The three processes in a thermodynamic cycle shown in the figure are: Process $1 \rightarrow 2$ is isothermal; Process $2 \rightarrow 3$ is isochoric (volume remains constant); Process $3 \rightarrow 1$ is adiabatic. The total work done by the ideal gas in this cycle is $10 \, J$. The internal energy decreases by $20 \, J$ in the isochoric process. The work done by the gas in the adiabatic process is $-20 \, J$. The heat added to the system in the isothermal process is .............. $J$.

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