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(B) Let the mass of each gas be $32 \ g$. Number of moles of $H_2$ $(n_{H_2})$ = $\frac{32 \ g}{2 \ g/mol} = 16 \ mol$. Number of moles of $O_2$ $(n_{

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(B) Let the mass of each gas be $32 \ g$. Number of moles of $H_2$ $(n_{H_2})$ = $\frac{32 \ g}{2 \ g/mol} = 16 \ mol$. Number of moles of $O_2$ $(n_{O_2})$ = $\frac{32 \ g}{32 \ g/mol} = 1 \ mol$. Number of moles of $CH_4$ $(n_{CH_4})$ = $\frac{32 \ g}{16 \ g/mol} = 2 \ mol$. Total moles = $16 + 1 + 2 = 19 \ mol$. Mole fraction of $CH_4$ $(x_{CH_4})$ = $\frac{n_{CH_4}}{	ext{Total moles}} = \frac{2}{19}$. Partial pressure of $CH_4$ $(P_{CH_4})$ = $x_{CH_4} 	imes P_{total} = \frac{2}{19} 	imes 380 \ torr = 40 \ torr$.

$A$ gaseous mixture contains equal masses of dihydrogen gas,dioxygen gas and methane gas at a total pressure of $380 \ torr$. The partial pressure of methane gas is ........... $torr$.

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