A General,while arranging his men,who were 60 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the number of men standing in each row be $x$.The total number of men arranged in a square formation is given by $x^2$.According to the proble

Vedclass · Accepted Answer

$77$

Vedclass · Answer

(B) Let the number of men standing in each row be $x$.The total number of men arranged in a square formation is given by $x^2$.According to the problem,the total number of men is $6000$,and $71$ men are left over after forming the square.Therefore,the equation is: $x^2 + 71 = 6000$.Subtracting $71$ from both sides,we get: $x^2 = 6000 - 71 = 5929$.To find $x$,we calculate the square root of $5929$: $x = \sqrt{5929} = 77$.Thus,there were $77$ men arranged in each row.

$A$ General,while arranging his men,who were $6000$ in number,in the form of a square,found that there were $71$ men leftover. How many were arranged in each row?

Similar Questions

$\Delta ABC$ is similar to $\Delta PQR$. The length of $AB$ is $16 \ cm$ and the length of the corresponding side $PQ$ is $9 \ cm$. If the area of $\Delta ABC$ is $1024 \ cm^2$,what is the area of $\Delta PQR$ in $cm^2$?

In a right-angled triangle,find the hypotenuse if the base and perpendicular are respectively $36015 \ cm$ and $48020 \ cm$.

If the area of a square is increased by $44 \%$,while retaining its shape as a square,by what percentage does each of its sides increase?

The area of a square field is $69696 \text{ cm}^2$. Its diagonal will be equal to (in $\text{cm}$) (in $.296$)

$2$ poles of heights $15\, m$ and $30\, m$ stand upright on a playground. If their feet are $36\, m$ apart,find the distance between their tops in meters.

Vedclass Test Series

Exam Paper Generator

Online Exam Module