A girl stands on a box having 60 ,cm length,4 | vedclass

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(B) Pressure $(P)$ is defined as force $(F)$ divided by the area $(A)$ over which it acts,given by the formula $P = F/A$.Since the weight of the box (

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maximum when breadth and width form the base

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(B) Pressure $(P)$ is defined as force $(F)$ divided by the area $(A)$ over which it acts,given by the formula $P = F/A$.Since the weight of the box (force) remains constant in all three cases,the pressure is inversely proportional to the surface area $(P \propto 1/A)$.To obtain the maximum pressure,the surface area of the base must be the minimum.The three possible base areas are:$1$. Length $	imes$ Breadth = $60 \,cm 	imes 40 \,cm = 2400 \,cm^2$$2$. Breadth $	imes$ Width = $40 \,cm 	imes 20 \,cm = 800 \,cm^2$$3$. Width $	imes$ Length = $20 \,cm 	imes 60 \,cm = 1200 \,cm^2$Comparing these,the minimum area is $800 \,cm^2$,which occurs when the breadth and width form the base.Therefore,the pressure is maximum when the breadth and width form the base.

$A$ girl stands on a box having $60 \,cm$ length,$40 \,cm$ breadth,and $20 \,cm$ width in three ways. In which of the following cases will the pressure exerted by the box be maximum?

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