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(B) The critical angle $	heta_c$ is given by the relation $\sin 	heta_c = \frac{1}{\mu}$.Since the refractive index $\mu$ depends on the wavelength

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The spectrum of visible light whose frequency is less than that of green light will come out to the air medium.

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(B) The critical angle $	heta_c$ is given by the relation $\sin 	heta_c = \frac{1}{\mu}$.Since the refractive index $\mu$ depends on the wavelength $\lambda$ (Cauchy's equation: $\mu \approx A + \frac{B}{\lambda^2}$),$\mu$ decreases as wavelength increases.Frequency $f$ is inversely proportional to wavelength $(f = \frac{c}{\lambda})$,so $\mu$ decreases as frequency decreases.For green light,$\sin 	heta_c = \frac{1}{\mu_{green}}$.Light with a frequency less than green light has a longer wavelength,resulting in a smaller refractive index $\mu$ and a larger critical angle $	heta_c$.Since the incident angle is fixed at $	heta_c$ (for green light),these colors (lower frequency) will have an incident angle less than their respective critical angles,allowing them to refract into the air.Conversely,light with a higher frequency has a larger $\mu$ and a smaller critical angle,causing it to undergo total internal reflection.

$A$ green light is incident from the water to the air-water interface at the critical angle $(\theta_c)$. Select the correct statement.

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