A heavy steel ball of mass greater than 1, kg | vedclass

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(B) Let $M$ be the mass of the heavy steel ball and $m$ be the mass of the ping-pong ball,where $M \gg m$.Let $u_1 = 2\, m/s$ be the initial velocity

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$4$

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(B) Let $M$ be the mass of the heavy steel ball and $m$ be the mass of the ping-pong ball,where $M \gg m$.Let $u_1 = 2\, m/s$ be the initial velocity of the steel ball and $u_2 = 0$ be the initial velocity of the ping-pong ball.The final velocity $v_2$ of the lighter body after an elastic head-on collision is given by the formula:$v_2 = \frac{2M}{M+m} u_1 + \frac{m-M}{M+m} u_2$Since $u_2 = 0$,this simplifies to $v_2 = \frac{2M}{M+m} u_1$.Given $M \gg m$,we can approximate $M+m \approx M$.Therefore,$v_2 \approx \frac{2M}{M} u_1 = 2 u_1$.Substituting $u_1 = 2\, m/s$,we get $v_2 \approx 2 	imes 2 = 4\, m/s$.

$A$ heavy steel ball of mass greater than $1\, kg$ moving with a speed of $2\, m/s$ collides head-on with a stationary ping-pong ball of mass less than $0.1\, g$. The collision is elastic. After the collision,the ping-pong ball moves approximately with a speed of ......... $m/s$.

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