A hemispherical bowl of internal radius 9 ,cm | vedclass

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(D) Given,radius of the hemispherical bowl,$r = 9 \,cm$.The volume of the hemispherical bowl is $V_{bowl} = \frac{2}{3} \pi r^3 = \frac{2}{3} 	imes \

Vedclass · Accepted Answer

$54$

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(D) Given,radius of the hemispherical bowl,$r = 9 \,cm$.The volume of the hemispherical bowl is $V_{bowl} = \frac{2}{3} \pi r^3 = \frac{2}{3} 	imes \pi 	imes 9^3 = \frac{2}{3} 	imes \pi 	imes 729 = 486 \pi \,cm^3$.Radius of each cylindrical bottle,$R = 1.5 \,cm$ and height,$h = 4 \,cm$.The volume of one cylindrical bottle is $V_{bottle} = \pi R^2 h = \pi 	imes (1.5)^2 	imes 4 = \pi 	imes 2.25 	imes 4 = 9 \pi \,cm^3$.Number of bottles required $= \frac{V_{bowl}}{V_{bottle}} = \frac{486 \pi}{9 \pi} = 54$.Therefore,$54$ bottles are needed to empty the bowl.

$A$ hemispherical bowl of internal radius $9 \,cm$ is full of liquid. The liquid is to be filled into cylindrical shaped bottles each of radius $1.5 \,cm$ and height $4 \,cm$. How many bottles are needed to empty the bowl?

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