A hemispherical bowl of radius 18, cm is comp | vedclass

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(A) The volume of the hemispherical bowl is given by $V_h = \frac{2}{3} \pi r^3$,where $r = 18\, cm$.$V_h = \frac{2}{3} 	imes \pi 	imes (18)^3 = \fr

Vedclass · Accepted Answer

$243$

Vedclass · Answer

(A) The volume of the hemispherical bowl is given by $V_h = \frac{2}{3} \pi r^3$,where $r = 18\, cm$.$V_h = \frac{2}{3} 	imes \pi 	imes (18)^3 = \frac{2}{3} 	imes \pi 	imes 5832 = 3888\pi\, cm^3$.The volume of one cylindrical bottle is given by $V_c = \pi R^2 h$,where $R = 2\, cm$ and $h = 4\, cm$.$V_c = \pi 	imes (2)^2 	imes 4 = \pi 	imes 4 	imes 4 = 16\pi\, cm^3$.The number of bottles required is $n = \frac{V_h}{V_c} = \frac{3888\pi}{16\pi} = 243$.Therefore,$243$ bottles are required.

$A$ hemispherical bowl of radius $18\, cm$ is completely filled with medicine. This medicine is to be filled in cylindrical bottles of radius $2\, cm$ and height $4\, cm$. How many bottles are required to empty the bowl?

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