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(D) Since only the rounded surface of the dome is to be painted,we need to find the curved surface area of the hemisphere.Circumference of the base of

Vedclass · Accepted Answer

$Rs. 24640$

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(D) Since only the rounded surface of the dome is to be painted,we need to find the curved surface area of the hemisphere.Circumference of the base of the dome $= 17.6 \, m$.Let the radius be $r$. Then,$2\pi r = 17.6$.$r = \frac{17.6}{2 	imes \pi} = \frac{17.6 	imes 7}{2 	imes 22} = 0.8 	imes 3.5 = 2.8 \, m$.Curved surface area of the hemisphere $= 2\pi r^2 = 2 	imes \frac{22}{7} 	imes 2.8 	imes 2.8 = 49.28 \, m^2$.Cost of painting $100 \, cm^2 = Rs. 5$.Since $1 \, m^2 = 10000 \, cm^2$,the cost of painting $1 \, m^2 = \frac{5}{100} 	imes 10000 = Rs. 500$.Total cost of painting $= 49.28 	imes 500 = Rs. 24640$.

$A$ hemispherical dome of a building needs to be painted. If the circumference of the base of the dome is $17.6 \, m$,find the cost of painting it,given the cost of painting is $Rs. 5$ per $100 \, cm^2$.

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