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(B) According to Pascal's Law, the pressure applied to an enclosed fluid is transmitted undiminished to every portion of the fluid and the walls of th

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$1000$

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(B) According to Pascal's Law, the pressure applied to an enclosed fluid is transmitted undiminished to every portion of the fluid and the walls of the containing vessel.Therefore, the pressure at both arms must be equal for equilibrium:$\frac{F_1}{A_1} = \frac{F_2}{A_2}$Here, $F_1$ is the force on the thicker arm, $A_1$ is the area of the thicker arm, $F_2 = 10 \,N$ is the force on the thinner arm, and $A_2$ is the area of the thinner arm.The diameter of the thicker arm is $D_1 = 14 \,cm$, so its radius is $r_1 = 7 \,cm$.The diameter of the thinner arm is $D_2 = 1.4 \,cm$, so its radius is $r_2 = 0.7 \,cm$.Substituting the areas $A = \pi r^2$:$\frac{F_1}{\pi (7)^2} = \frac{10}{\pi (0.7)^2}$$F_1 = 10 	imes \frac{49}{0.49}$$F_1 = 10 	imes 100 = 1000 \,N$.

$A$ hydraulic press containing water has two arms with diameters as shown in the figure. $A$ force of $10 \,N$ is applied on the surface of water in the thinner arm. The force required to be applied on the surface of water in the thicker arm to maintain equilibrium of water is . . . . . . $N$.

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