A hydrocarbon 'X' with formula C_6H_8 uses tw | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. The hydrocarbon '$X$' has the molecular formula $C_6H_8$.$2$. It consumes two moles of $H_2$ upon catalytic hydrogenation,indicating the pres

Vedclass · Accepted Answer

cyclohexa$-1, 4-$diene

Vedclass · Answer

(D) $1$. The hydrocarbon '$X$' has the molecular formula $C_6H_8$.$2$. It consumes two moles of $H_2$ upon catalytic hydrogenation,indicating the presence of two double bonds.$3$. Ozonolysis of '$X$' yields two moles of methane dicarbaldehyde $(OHC-CH_2-CHO)$.$4$. Methane dicarbaldehyde is also known as malonaldehyde.$5$. Cyclohexa$-1, 4-$diene undergoes ozonolysis to break the two double bonds,resulting in two molecules of $OHC-CH_2-CHO$.$6$. Therefore,the hydrocarbon '$X$' is cyclohexa$-1, 4-$diene.

$A$ hydrocarbon '$X$' with formula $C_6H_8$ uses two moles of $H_2$ on catalytic hydrogenation of its one mole. On ozonolysis,'$X$' yields two moles of methane dicarbaldehyde (malonaldehyde). The hydrocarbon '$X$' is :

Similar Questions

Taking into account the stability of various cycloalkanes and carbocations,as well as the rules governing mechanisms of carbocation rearrangements,what is the most likely product of this reaction?

One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular mass of $44 \ u$. The alkene is

The Diels-Alder reaction will not take place with which of the following reactants?

On vigorous oxidation by permanganate solution,$(CH_3)_2C = CH - CH_2CH_2CH_3$ gives:

Identify the products obtained in the ozonolysis of propene.

Vedclass Test Series

Exam Paper Generator

Online Exam Module