A lead ball strikes a wall and falls down,whi | vedclass

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(C) Change in momentum is defined as $\Delta \vec{P} = \vec{P}_{final} - \vec{P}_{initial}$.For the lead ball,it strikes the wall and falls down,so it

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The tennis ball suffers a greater change in momentum as compared with the lead ball.

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(C) Change in momentum is defined as $\Delta \vec{P} = \vec{P}_{final} - \vec{P}_{initial}$.For the lead ball,it strikes the wall and falls down,so its final velocity is $0$. Thus,$\Delta \vec{P}_{lead} = 0 - m\vec{v} = -m\vec{v}$. The magnitude of change is $m\vec{v}$.For the tennis ball,it bounces back with the same velocity $\vec{v}$ in the opposite direction,so its final velocity is $-\vec{v}$. Thus,$\Delta \vec{P}_{tennis} = m(-\vec{v}) - m\vec{v} = -2m\vec{v}$. The magnitude of change is $2m\vec{v}$.Comparing the magnitudes,$|\Delta \vec{P}_{tennis}| > |\Delta \vec{P}_{lead}|$. Therefore,the tennis ball suffers a greater change in momentum.

$A$ lead ball strikes a wall and falls down,while a tennis ball having the same mass and velocity strikes the wall and bounces back. Check the correct statement.

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