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(D) For a body of mass $M$ in a lift moving downwards with acceleration $a$,the normal reaction $R$ exerted by the floor is given by $R = M(g - a)$.Gi

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(D) For a body of mass $M$ in a lift moving downwards with acceleration $a$,the normal reaction $R$ exerted by the floor is given by $R = M(g - a)$.Given that the lift is moving downwards with an acceleration equal to the acceleration due to gravity,we have $a = g$.Substituting $a = g$ into the equation for normal reaction,we get $R = M(g - g) = 0$.The frictional force $f$ is given by $f = \mu R$.Since $R = 0$,the frictional resistance offered by the body is $f = \mu 	imes 0 = 0$.

$A$ lift is moving downwards with an acceleration equal to the acceleration due to gravity. $A$ body of mass $M$ kept on the floor of the lift is pulled horizontally. If the coefficient of friction is $\mu$,then the frictional resistance offered by the body is:

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