A light beam has an amplitude A,and the angle | vedclass

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(D) According to the law of Malus for amplitudes,the amplitude of the light transmitted through an analyser is given by $A' = A \cos 	heta$,where $A$

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$A/2$

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(D) According to the law of Malus for amplitudes,the amplitude of the light transmitted through an analyser is given by $A' = A \cos 	heta$,where $A$ is the initial amplitude and $	heta$ is the angle between the transmission axes of the polariser and the analyser.Given,$A = A$ and $	heta = 60^o$.Substituting the values,we get $A' = A \cos(60^o)$.Since $\cos(60^o) = 1/2$,the amplitude of the light transmitted by the analyser is $A' = A 	imes (1/2) = A/2$.

$A$ light beam has an amplitude $A$,and the angle between the analyser and the polariser is $60^o$. What is the amplitude of the light reflected by the analyser?

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