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(A) For a system of two masses $m_1$ and $m_2$ connected by a string over a pulley,the acceleration $a$ is given by the formula: $a = \frac{(m_1 - m_2

Vedclass · Accepted Answer

$9: 7$

Vedclass · Answer

(A) For a system of two masses $m_1$ and $m_2$ connected by a string over a pulley,the acceleration $a$ is given by the formula: $a = \frac{(m_1 - m_2)g}{m_1 + m_2}$ Given that $a = g / 8$,we substitute this into the equation: $\frac{g}{8} = \frac{(m_1 - m_2)g}{m_1 + m_2}$ $\frac{1}{8} = \frac{m_1 - m_2}{m_1 + m_2}$ $m_1 + m_2 = 8(m_1 - m_2)$ $m_1 + m_2 = 8m_1 - 8m_2$ $9m_2 = 7m_1$ $\frac{m_1}{m_2} = \frac{9}{7}$ Thus,the ratio $m_1 : m_2$ is $9: 7$.

$A$ light string passing over a smooth light pulley connects two blocks of masses $m_1$ and $m_2$ (vertically). If the acceleration of the system is $g / 8$,then the ratio of the masses $m_1 : m_2$ (assuming $m_1 > m_2$) is:

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