A liquid of density 10^3 , kg/m^3 and coeffic | vedclass

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(B) The Reynold's number $(R_e)$ is given by the formula: $R_e = \frac{\rho v D}{\eta}$ where $\rho$ is the density of the liquid, $v$ is the velocity

Vedclass · Accepted Answer

$1000$

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(B) The Reynold's number $(R_e)$ is given by the formula: $R_e = \frac{ho v D}{\eta}$ where $ho$ is the density of the liquid, $v$ is the velocity, $D$ is the diameter of the tube, and $\eta$ is the coefficient of viscosity. Given: Density $ho = 10^3 \, kg/m^3$ Velocity $v = 2 \, m/s$ Radius $r = 2 \, cm = 0.02 \, m$, so diameter $D = 2r = 0.04 \, m$ Coefficient of viscosity $\eta = 8 	imes 10^{-2} \, 	ext{decapoise} = 0.08 \, Pa \cdot s$ Substituting the values: $R_e = \frac{10^3 	imes 2 	imes 0.04}{8 	imes 10^{-2}}$ $R_e = \frac{1000 	imes 0.08}{0.08}$ $R_e = 1000$

$A$ liquid of density $10^3 \, kg/m^3$ and coefficient of viscosity $8 \times 10^{-2} \, \text{decapoise}$ is flowing in a tube of radius $2 \, cm$ with speed $2 \, m/s$. The Reynold's number is ..........

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