$A$ long copper tube of inner radius $R$ carries a current $i$. The magnetic field $B$ inside the tube is

  • A
    $\frac{\mu_0 i}{2\pi R}$
  • B
    $\frac{\mu_0 i}{4\pi R}$
  • C
    $\frac{\mu_0 i}{2R}$
  • D
    Zero

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