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(C) The magnetic field $\vec{B}$ produced by a long straight wire carrying current $I_1$ at a distance $r$ is given by $\vec{B} = \frac{\mu_0 I_1}{2\p

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(C) The magnetic field $\vec{B}$ produced by a long straight wire carrying current $I_1$ at a distance $r$ is given by $\vec{B} = \frac{\mu_0 I_1}{2\pi r} \hat{	heta}$.Since the loop is in the $x-y$ plane and the wire is along the $z$-axis,the magnetic field lines are circles in the $x-y$ plane centered at the wire.For any closed current loop in a non-uniform magnetic field,the net force is given by $\vec{F} = \oint I_2 (d\vec{l} 	imes \vec{B})$.However,a more fundamental property is that the magnetic field produced by a long straight wire is conservative in the region not containing the wire. Alternatively,consider the magnetic dipole moment $\vec{m}$ of the loop. The force on a magnetic dipole in a non-uniform magnetic field is $\vec{F} = 
abla (\vec{m} \cdot \vec{B})$.For a current loop not encircling the wire,the net magnetic flux through the loop is zero because the magnetic field lines enter and leave the loop area in a way that cancels out. By symmetry and the properties of the magnetic field of an infinite wire,the net force on a closed current loop that does not encircle the wire is zero.

$A$ long straight wire is carrying current $I_1$ in the $+z$ direction. The $x-y$ plane contains a closed circular loop carrying current $I_2$ and does not encircle the straight wire. The net force on the loop will be:

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