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(D) Let $q_{m}$ be the pole strength of the magnetized steel wire.The initial magnetic moment is given by $M = q_{m} L$.When the wire is bent into a s

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$2M/\pi$

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(D) Let $q_{m}$ be the pole strength of the magnetized steel wire.The initial magnetic moment is given by $M = q_{m} L$.When the wire is bent into a semicircular arc,the length $L$ becomes the circumference of the semicircle,so $\pi r = L$,which implies $r = L/\pi$.The new magnetic moment $M^{\prime}$ is the product of the pole strength and the straight-line distance between the two poles (the diameter of the semicircle).$M^{\prime} = q_{m} 	imes (2r) = q_{m} 	imes (2L/\pi)$.Substituting $M = q_{m} L$,we get $M^{\prime} = 2M/\pi$.

$A$ magnetized steel wire of length $L$ has a magnetic moment $M$. It is then bent into a semicircular arc. The new magnetic moment is:

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