A man can do a work in 10, days. With the hel | vedclass

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Question

(A) man can complete a work in $10\, days$.(Man + boy) can complete the same work in $6\, days$.Let the total work be the Least Common Multiple of $10

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(A) man can complete a work in $10\, days$.(Man + boy) can complete the same work in $6\, days$.Let the total work be the Least Common Multiple of $10$ and $6$,which is $30\, units$.Efficiency of the man $= 30 / 10 = 3\, units/day$.Efficiency of (man + boy) $= 30 / 6 = 5\, units/day$.Efficiency of the boy $= 5 - 3 = 2\, units/day$.Since wages are distributed in proportion to the work done,the share of the boy is calculated based on his efficiency relative to the total efficiency.Share of the boy $= (2 / 5) 	imes 50 = Rs.\, 20$.

$A$ man can do a work in $10\, days$. With the help of a boy,he can do the same work in $6\, days$. If they get $Rs.\, 50$ for that work,what is the share of that boy? (in $Rs.$)

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