A man can row 30 text{ km} downstream and ret | vedclass

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(B) Let the speed of the stream be $x 	ext{ km/h}$.Since the speed of the boat in still water is $4$ times the speed of the current,the speed of the

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(B) Let the speed of the stream be $x 	ext{ km/h}$.Since the speed of the boat in still water is $4$ times the speed of the current,the speed of the boat in still water is $4x 	ext{ km/h}$.The speed downstream is $(4x + x) = 5x 	ext{ km/h}$.The speed upstream is $(4x - x) = 3x 	ext{ km/h}$.Given that the total time taken for the round trip of $30 	ext{ km}$ is $8 	ext{ h}$,we use the formula $	ext{Time} = \frac{	ext{Distance}}{	ext{Speed}}$.$\frac{30}{3x} + \frac{30}{5x} = 8$.$\frac{10}{x} + \frac{6}{x} = 8$.$\frac{16}{x} = 8$.$x = \frac{16}{8} = 2 	ext{ km/h}$.Thus,the speed of the current is $2 	ext{ km/h}$.

$A$ man can row $30 \text{ km}$ downstream and return in a total of $8 \text{ h}$. If the speed of the boat in still water is $4$ times the speed of the current,then the speed of the current is ....... $\text{km/h}$.

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