$A$ man can see only between $75 \, cm$ and $100 \, cm$. The power of the lens required to correct the near point will be:

  • A
    $+ \frac{8}{3} \, D$
  • B
    $+ 3 \, D$
  • C
    $- 3 \, D$
  • D
    $-\frac{8}{3} \, D$

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