A man divides his property such that his son' | vedclass

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(A) Let the shares of the son,wife,and daughter be $S$,$W$,and $D$ respectively.Given ratios are $S:W = 3:1$ and $W:D = 3:1$.To combine these ratios,w

Vedclass · Accepted Answer

$16250$

Vedclass · Answer

(A) Let the shares of the son,wife,and daughter be $S$,$W$,and $D$ respectively.Given ratios are $S:W = 3:1$ and $W:D = 3:1$.To combine these ratios,we make the wife's share $(W)$ common in both ratios.$S:W = 3:1 = 9:3$ and $W:D = 3:1$.Thus,the combined ratio is $S:W:D = 9:3:1$.Let the shares be $9k$,$3k$,and $k$ respectively,where $k$ is a constant.The total property value is $9k + 3k + k = 13k$.According to the problem,the daughter gets ₹ $10,000$ less than the son:$S - D = 10000$$9k - k = 10000$$8k = 10000$$k = 1250$.The total property value is $13k = 13 	imes 1250 = 16250$.Therefore,the total value of the property is ₹ $16,250$.

$A$ man divides his property such that his son's share to his wife's share and his wife's share to his daughter's share are both in the ratio $3:1$. If the daughter gets ₹ $10,000$ less than the son,what is the total value of the property in ₹?

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