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(B) Let the distances of the two cliffs from the man be $d_1$ and $d_2$ respectively.The time taken for the first echo to return is $t_1 = 3 \ s$.The

Vedclass · Accepted Answer

$1320$

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(B) Let the distances of the two cliffs from the man be $d_1$ and $d_2$ respectively.The time taken for the first echo to return is $t_1 = 3 \ s$.The distance traveled by sound for the first echo is $2d_1 = v 	imes t_1$.$2d_1 = 330 	imes 3 = 990 \ m \implies d_1 = 495 \ m$.The time taken for the second echo to return is $t_2 = 5 \ s$.The distance traveled by sound for the second echo is $2d_2 = v 	imes t_2$.$2d_2 = 330 	imes 5 = 1650 \ m \implies d_2 = 825 \ m$.The total distance between the two cliffs is $D = d_1 + d_2$.$D = 495 + 825 = 1320 \ m$.

$A$ man fires a bullet standing between two cliffs. The first echo is heard after $3 \ s$ and the second echo is heard after $5 \ s$. If the velocity of sound is $330 \ m/s$,then the distance between the cliffs is .... $m$.

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