A man invested frac{1}{3} of his capital at 7 | vedclass

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(C) Let the total capital be $x$.The investments are:$1$. $\frac{x}{3}$ at $7 \% = \frac{x}{3} 	imes \frac{7}{100} = \frac{7x}{300}$$2$. $\frac{x}{4}

Vedclass · Accepted Answer

$6600$

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(C) Let the total capital be $x$.The investments are:$1$. $\frac{x}{3}$ at $7 \% = \frac{x}{3} 	imes \frac{7}{100} = \frac{7x}{300}$$2$. $\frac{x}{4}$ at $8 \% = \frac{x}{4} 	imes \frac{8}{100} = \frac{8x}{400} = \frac{2x}{100} = \frac{6x}{300}$$3$. The remainder is $x - (\frac{x}{3} + \frac{x}{4}) = x - \frac{7x}{12} = \frac{5x}{12}$.Interest on the remainder at $10 \% = \frac{5x}{12} 	imes \frac{10}{100} = \frac{50x}{1200} = \frac{x}{24}$.Total annual income is given as ₹ $561$:$\frac{7x}{300} + \frac{6x}{300} + \frac{x}{24} = 561$$\frac{13x}{300} + \frac{x}{24} = 561$Finding the common denominator $(600)$:$\frac{26x + 25x}{600} = 561$$\frac{51x}{600} = 561$$x = \frac{561 	imes 600}{51}$$x = 11 	imes 600 = 6600$Therefore,the total capital is ₹ $6600$.

$A$ man invested $\frac{1}{3}$ of his capital at $7 \%$,$\frac{1}{4}$ at $8 \%$,and the remainder at $10 \%$. If the annual income is ₹ $561$,the capital (in ₹) is:

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