A man invested Rs. 50490 in 5% stock at 99 an | vedclass

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Question

(A) $1$. Purchase price of the first stock (including brokerage) $= Rs. (99 + 3) = Rs. 102$.$2$. Number of shares purchased $= \frac{50490}{102} = 495

Vedclass · Accepted Answer

$1485$

Vedclass · Answer

(A) $1$. Purchase price of the first stock (including brokerage) $= Rs. (99 + 3) = Rs. 102$.$2$. Number of shares purchased $= \frac{50490}{102} = 495$.$3$. Income from the first stock $= 5\% 	ext{ of } (495 	imes 100) = \frac{5}{100} 	imes 49500 = Rs. 2475$.$4$. Sale price of the first stock (after deducting brokerage) $= Rs. (102 - 3) = Rs. 99$.$5$. Total amount received from the sale $= 495 	imes 99 = Rs. 49005$.$6$. Purchase price of the second stock (including brokerage) $= Rs. (96 + 3) = Rs. 99$.$7$. Number of shares purchased in the second stock $= \frac{49005}{99} = 495$.$8$. Income from the second stock $= 8\% 	ext{ of } (495 	imes 100) = \frac{8}{100} 	imes 49500 = Rs. 3960$.$9$. Change in income $= Rs. (3960 - 2475) = Rs. 1485$.

$A$ man invested $Rs. 50490$ in $5\%$ stock at $99$ and sold it when the price rose to $Rs. 102$. He invested the sale proceeds in $8\%$ stock at $96$. Find out the change in the man's income (Brokerage: $Rs. 3$).

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