A man leaves for his office from his house. H | vedclass

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(B) Let the starting point be $O$. $1$. The man moves $20 \,m$ East to reach point $A$. $2$. He turns South and moves $10 \,m$ to reach point $B$. $3$

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) Let the starting point be $O$. $1$. The man moves $20 \,m$ East to reach point $A$. $2$. He turns South and moves $10 \,m$ to reach point $B$. $3$. He turns West and moves $35 \,m$ to reach point $C$. $4$. He turns North and moves $5 \,m$ to reach point $D$. $5$. He turns East and moves $15 \,m$ to reach point $E$. Let's use a coordinate system where the starting point $O$ is $(0, 0)$. - After $20 \,m$ East: $(20, 0)$. - After $10 \,m$ South: $(20, -10)$. - After $35 \,m$ West: $(20 - 35, -10) = (-15, -10)$. - After $5 \,m$ North: $(-15, -10 + 5) = (-15, -5)$. - After $15 \,m$ East: $(-15 + 15, -5) = (0, -5)$. The final position is $(0, -5)$. The initial position is $(0, 0)$. The straight distance is the magnitude of the displacement vector: $\sqrt{(0-0)^2 + (-5-0)^2} = \sqrt{0 + 25} = 5 \,m$.

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