A man of blood group-A marries a woman of blo | vedclass

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Question

(A) The man is heterozygous for blood group-$A$,so his genotype is $I^A I^O$.The woman is heterozygous for blood group-$B$,so her genotype is $I^B I^O

Vedclass · Accepted Answer

$25$

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(A) The man is heterozygous for blood group-$A$,so his genotype is $I^A I^O$.The woman is heterozygous for blood group-$B$,so her genotype is $I^B I^O$.When these two individuals cross $(I^A I^O 	imes I^B I^O)$,the possible genotypes of the offspring are:$1. I^A I^B$ (Blood group $AB$)$2. I^A I^O$ (Blood group $A$)$3. I^B I^O$ (Blood group $B$)$4. I^O I^O$ (Blood group $O$)Each genotype has a probability of $25\, \%$. Therefore,the chance of the first child having blood group $AB$ is $25\, \%$.

Genotype	Blood group
$I^{A} I^{A}$	$A$
$W$	$A$
$I^{B} I^{B}$	$B$
$X$	$B$
$I^{A} I^{B}$	$Y$
$Z$	$O$

$A$ man of blood group-$A$ marries a woman of blood group-$B$. Both of them are heterozygous for their blood group. The chances of their first child having blood group $AB$ will be: (in $, \%$)

Similar Questions

The following table is regarding $ABO$ blood group. Identify $W, X, Y, Z$.
Genotype Blood group
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$W$ $A$
$I^{B} I^{B}$ $B$
$X$ $B$
$I^{A} I^{B}$ $Y$
$Z$ $O$

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