A man with normal vision whose father was col | vedclass

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(D) The man has normal vision,so his genotype is $X^CY$. Since his father was colourblind,the man received his $Y$ chromosome from his father and his

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(D) The man has normal vision,so his genotype is $X^CY$. Since his father was colourblind,the man received his $Y$ chromosome from his father and his $X^C$ chromosome from his mother,but he is phenotypically normal,meaning he carries the dominant allele. Wait,if the man has normal vision,his genotype is $X^CY$. The woman's father was colourblind,so she must be a carrier $(X^CX^c)$. When a normal man $(X^CY)$ marries a carrier woman $(X^CX^c)$,the possible genotypes for their daughters are $X^CX^C$ (normal) and $X^CX^c$ (carrier). Neither of these genotypes results in colourblindness for the daughter,as colourblindness is a recessive $X$-linked trait requiring the daughter to inherit the recessive allele from both parents. Since the father is normal $(X^CY)$,he cannot pass the recessive allele to his daughter. Therefore,the chance of the daughter being colourblind is $0 \%$.

$A$ man with normal vision whose father was colourblind marries a woman whose father was also colourblind. Suppose their first child is a daughter,what are the chances of this child being colourblind (in $\%$)?

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