A man's wages were decreased by 50 %. Again,t | vedclass

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(B) Let the initial wage be $100$.After a decrease of $50 \%$,the new wage becomes $100 - (50 \% 	ext{ of } 100) = 100 - 50 = 50$.Now,the reduced wag

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$25 \%$

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(B) Let the initial wage be $100$.After a decrease of $50 \%$,the new wage becomes $100 - (50 \% 	ext{ of } 100) = 100 - 50 = 50$.Now,the reduced wage is increased by $50 \%$,so the final wage becomes $50 + (50 \% 	ext{ of } 50) = 50 + 25 = 75$.The total loss is $100 - 75 = 25$.Therefore,the percentage loss is $\frac{25}{100} 	imes 100 = 25 \%$.Alternatively,using the net percentage change formula: $	ext{Net change} = \left(x + y + \frac{xy}{100}ight) \%$,where $x = -50$ and $y = 50$.$	ext{Net change} = -50 + 50 + \frac{(-50 	imes 50)}{100} = 0 - 25 = -25 \%$.The negative sign indicates a loss of $25 \%$.

$A$ man's wages were decreased by $50 \%$. Again,the reduced wages were increased by $50 \%$. He has a loss of:

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