A mass is performing vertical circular motion | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The tension $T$ at any point in a vertical circular motion is given by:$T = \frac{mv^2}{l} + mg \cos 	heta$where $	heta$ is the angular displace

Vedclass · Accepted Answer

$B$

Vedclass · Answer

(B) The tension $T$ at any point in a vertical circular motion is given by:$T = \frac{mv^2}{l} + mg \cos 	heta$where $	heta$ is the angular displacement from the lowest point,$l$ is the length of the string,and $m$ is the mass of the particle.At the lowest point $(B)$,$	heta = 0^\circ$,so $\cos 	heta = 1$,and the tension is $T_B = \frac{mv_B^2}{l} + mg$.At the highest point $(A)$,$	heta = 180^\circ$,so $\cos 	heta = -1$,and the tension is $T_A = \frac{mv_A^2}{l} - mg$.It is clear that the tension is maximum at the lowest point $(B)$ because the centripetal force and the component of gravity both contribute to the tension. If the average velocity of the particle is increased,the tension at the lowest point will increase the most. Therefore,the string has the maximum probability of breaking at point $B$.

$A$ mass is performing vertical circular motion (see figure). If the average velocity of the particle is increased,then at which point will the string break?

Similar Questions

$A$ particle is rotated in a vertical circle by connecting it to a light rod of length $l$ and keeping the other end of the rod fixed. The minimum speed of the particle when the light rod is horizontal for which the particle will complete the circle is

$A$ body of mass $m$ hangs at one end of a string of length $l$,the other end of which is fixed. It is given a horizontal velocity such that the string just reaches a position where it makes an angle of $60^{\circ}$ with the vertical. The tension in the string at the mean position is:

$A$ fighter plane is moving in a vertical circle of radius $r$. Its minimum velocity at the highest point of the circle will be

Consider a particle moving with a minimum speed $v$ at the highest point of a vertical circle of radius $R$. If the radius of the circle is doubled, the corresponding minimum speed will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module