A mass of 10 , kg is suspended vertically by | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the tension in the upper half of the rope be $T_1$ and the tension in the lower half be $T_2$. The lower half of the rope supports the mass $m

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(D) Let the tension in the upper half of the rope be $T_1$ and the tension in the lower half be $T_2$. The lower half of the rope supports the mass $m = 10 \, kg$,so $T_2 = mg = 10 	imes 10 = 100 \, N$.At the middle point where the horizontal force $F = 30 \, N$ is applied,we consider the equilibrium of forces in the horizontal and vertical directions.For horizontal equilibrium: $T_1 \sin 	heta = F = 30 \, N$.For vertical equilibrium: $T_1 \cos 	heta = T_2 = 100 \, N$.Dividing the two equations: $\frac{T_1 \sin 	heta}{T_1 \cos 	heta} = \frac{30}{100} \Rightarrow 	an 	heta = 0.3$.Given $	heta = 	an^{-1}(x 	imes 10^{-1})$,we have $	an 	heta = x 	imes 10^{-1} = \frac{x}{10}$.Equating the two expressions for $	an 	heta$: $\frac{x}{10} = 0.3 \Rightarrow x = 3$.

Similar Questions

In the figure, the tension in the horizontal cord is $30\,N$. Find the weight of the body $B$.

In the given arrangement,the normal force applied by the block on the ground is

$A$ body is moving under the action of two forces $\vec{F}_1 = 2\hat{i} - 5\hat{j}$ and $\vec{F}_2 = 3\hat{i} - 4\hat{j}$. Its velocity will become uniform under an additional third force $\vec{F}_3$ given by:

$A$ $1 \text{ N}$ pendulum bob is held at an angle $\theta$ from the vertical by a $2 \text{ N}$ horizontal force $F$ as shown in the figure. The tension in the string supporting the pendulum bob (in newton) is

$A$ block of mass $90 \,kg$ is suspended by three strings $A, B$ and $C$ as shown in the figure. Find the tensions in the strings $A, B$ and $C$ respectively. $\left(g=10 \,ms^{-2}, \sin 37^{\circ}=0.6, \cos 37^{\circ}=0.8\right)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module