$A$ metal chloride contains $55.0 \%$ of chlorine by weight. $100 \ mL$ of vapours of the metal chloride at $STP$ weigh $0.57 \ g$. The molecular formula of the metal chloride is $...$. (Given: Atomic mass of chlorine is $35.5 \ u$)
- A$MCl_2$
- B$MCl_4$
- C$MCl_3$
- D$MCl$
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Similar Questions
In the reaction $SO_{2(g)} + 1/2 O_{2(g)} \to SO_{3(g)}$,how many liters of air at $STP$ are required for the complete conversion of $6.4 \, g$ of $SO_2$ to $SO_3$ (in $, L$)? (Assume air contains $20 \% \, O_2$ by volume).
Difficult
View SolutionIf the density of liquid $HCl$ is $1.17 \, g \, cm^{-3}$,then its molarity will be ...............
Difficult
View SolutionMatch the following and select the correct option:
List-$I$ List-$II$ (At $STP$) $(A)$ $10 \ g \ CaCO_3 \xrightarrow{\Delta} \text{decomposition}$ $(i)$ $0.224 \ L \ CO_2$ $(B)$ $1.06 \ g \ Na_2CO_3 \xrightarrow{\text{Excess } HCl}$ $(ii)$ $4.48 \ L \ CO_2$ $(C)$ $2.4 \ g \ C \xrightarrow{\text{Excess } O_2} \text{combustion}$ $(iii)$ $0.448 \ L \ CO_2$ $(D)$ $0.56 \ g \ CO \xrightarrow{\text{Excess } O_2} \text{combustion}$ $(iv)$ $2.24 \ L \ CO_2$ $(v)$ $22.4 \ L \ CO_2$
| List-$I$ | List-$II$ (At $STP$) |
| $(A)$ $10 \ g \ CaCO_3 \xrightarrow{\Delta} \text{decomposition}$ | $(i)$ $0.224 \ L \ CO_2$ |
| $(B)$ $1.06 \ g \ Na_2CO_3 \xrightarrow{\text{Excess } HCl}$ | $(ii)$ $4.48 \ L \ CO_2$ |
| $(C)$ $2.4 \ g \ C \xrightarrow{\text{Excess } O_2} \text{combustion}$ | $(iii)$ $0.448 \ L \ CO_2$ |
| $(D)$ $0.56 \ g \ CO \xrightarrow{\text{Excess } O_2} \text{combustion}$ | $(iv)$ $2.24 \ L \ CO_2$ |
| $(v)$ $22.4 \ L \ CO_2$ |
$56.0 \ L$ of nitrogen gas is mixed with excess of hydrogen gas and it is found that $20 \ L$ of ammonia gas is produced. The volume of unused nitrogen gas is found to be $L$.
The volume of $0.1 \, M$ $H_2SO_4$ that is needed to completely neutralize $40 \, mL$ of $0.2 \, M$ $NaOH$ is $..... \, mL$.
Medium
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