$A$ metal conductor of length $1\;m$ rotates vertically about one of its ends at an angular velocity of $5\;rad/s$. If the horizontal component of the Earth's magnetic field is $0.2 \times 10^{-4}\;T$,then the $e.m.f.$ developed between the two ends of the conductor is:

  • A
    $5\;mV$
  • B
    $5 \times 10^{-4}\;V$
  • C
    $50\;mV$
  • D
    $50\;\mu V$

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