A metal nitrate reacts with KI to give a blac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction of bismuth nitrate with potassium iodide $(KI)$ produces a black precipitate of bismuth$(III)$ iodide $(BiI_3)$.$Bi(NO_3)_3(aq) + 3KI

Vedclass · Accepted Answer

$Bi^{3+}$

Vedclass · Answer

(B) The reaction of bismuth nitrate with potassium iodide $(KI)$ produces a black precipitate of bismuth$(III)$ iodide $(BiI_3)$.$Bi(NO_3)_3(aq) + 3KI(aq) \xrightarrow{\quad} BiI_3(s) + 3KNO_3(aq)$Upon adding an excess of $KI$,the black precipitate dissolves to form a soluble complex,potassium tetraiodobismuthate$(III)$,which is orange in color.$BiI_3(s) + KI(aq) \xrightarrow{\quad} K[BiI_4](aq)$Thus,the cation is $Bi^{3+}$.

$A$ metal nitrate reacts with $KI$ to give a black precipitate which on addition of excess of $KI$ converts into an orange-colored solution. The cation of the metal nitrate is

Similar Questions

Aqueous solution of Mohr's salt gives the test of which ions?

Which of the following ions forms a colored carbonate precipitate?

Which reagents are used for the identification of Group $IV$ cations?

Which of the following cations will give a precipitate with $Na_2C_2O_4$ solution in the presence of acetic acid?

Which reagent is used to test for the presence of the $Fe^{+2}$ ion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module